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I am having some troubles with the document.querySelectorAll() because, I don't know why, it doesn't work when I add more than one class or ID. So, this is what I want to achieve: http://codepen.io/sonder15478/pen/PpJqKN But there's a lot of code that I wouldn't need if I use document.querySelectorAll(). This is where I get stuck: http://codepen.io/sonder15478/pen/xqXGXm I also tried with getElementsByClassName(), but it didn't work either... Any ideas? Thank you!
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I am looking for a way to know the current position of a x,y tween. I am using the css plugin to move DOM elements around the screen. I'm not sure if I am overlooking something. I have searched the forums and documentation, and all I could find was the tip to hack a secretly hidden property of a tweened element: _gsTransform My question: is there no official way to get the x and y properties? Is this secret hack the only way? It seems a bit hacky to me, and it doesn't result in clean code. TweenLite.get() would be great! btw, this problem gets worse when you use typescript, since the typescript definition file does not include _gsTransform. In typescript, you will get this error when you try to read _gsTransform: let x = this.element._gsTransform.x // error: htmlElement has no property _gsTransform Of course, I can add _gsTransform manually, but that's even more hacky.
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Hi, How can I get the actual width of an element after scaling it with Tweenmax? Example: $('#myDiv').width(100); // Sets width of #myDiv to 100; TweenMax.set($('#myDiv'), {scale:1.2}); console.log($('#myDiv').width()); // gives 100 instead of 120 How can I get the actual width of the div? Thanks a lot in advance, this thing is frustrating me and breaking my head today...
