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Changing position by 2 ways (x and left)

gerasim9 test
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Go to solution Solved by OSUblake,

Warning: Please note

This thread was started before GSAP 3 was released. Some information, especially the syntax, may be out of date for GSAP 3. Please see the GSAP 3 migration guide and release notes for more information about how to update the code to GSAP 3's syntax. 

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1) div moves to 200 pixels to the right and takes the position 300px - it's ok
2) and next div moves to 50 pixels to the left - why? I thought it was specified the absolute position (left:50px)
And how I can move the block to the absolute position  (left:50px) at the second tween (if the first tween use  "x:..." )

var logo = document.getElementById("elem");
new TweenMax(logo, 2, {x:200});
new TweenMax(logo, 2, {css:{left:"50px"}}).delay(2);


<div style="left: 100px; top: 100px; position:absolute;" id="elem">blablabla</div>
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Yup, Blake's solution is what you should use.



This is just how CSS works when you combine transforms (x) and positions (left).

Your div will end up at left:50, but also be transformed 200px to the right.


Basically, what you are having GSAP do is this in CSS

/*this div will be 250 px from left of window*/
.green {
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